algorithm/BOJ
BOJ 1062번 가르침
_JunHo
2020. 2. 5. 23:57
BOJ : https://www.acmicpc.net/problem/1062
github : https://github.com/junho0956/Algorithm/blob/master/1062/1062/%EC%86%8C%EC%8A%A4.cpp
dfs를 통해서 사용가능한 알파벳의 추가/삭제 연산을 해주면서 완전탐색 하듯이 탐색하였습니다.
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#include <iostream>
#include <string>
#include <algorithm>
#include <vector>
using namespace std;
bool visit[26];
int N, K, ans;
vector<string> v;
void solve(int al, int pk) {
if (pk == K) {
int cnt = 0;
for (int i = 0; i < N; i++) {
bool temp = true;
for (int j = 4; j < v[i].size() - 4; j++) {
if (visit[v[i][j]-'a'] == false) {
temp = false;
break;
}
}
if (temp) cnt++;
}
ans = max(ans, cnt);
return;
}
for (int i = al; i < 26; i++) {
if (!visit[i]) {
visit[i] = 1;
solve(i, pk + 1);
visit[i] = 0;
}
}
}
int main() {
ios::sync_with_stdio(0), cin.tie(0);
visit['a' - 'a'] = visit['c' - 'a'] = visit['t' - 'a'] = visit['i' - 'a'] = visit['n' - 'a'] = true;
cin >> N >> K;
if (K < 5) ans = 0;
else if (K == 26) ans = N;
else {
string str;
for (int i = 0; i < N; i++) {
cin >> str;
v.push_back(str);
}
solve(0, 5);
}
cout << ans;
return 0;
}
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